Saturday, 19 October 2013

→sinθ=1/cosecθ
→cosθ=1/secθ
→tanθ=sinθ/cosθ
→cotθ=cosθ/sinθ
→secθ=1/cosθ
→cosecθ=1/sinθ

Pythagorean Identities:-

  • sin²θ+cos²θ=1
  • tan²θ+1=sec²θ
  • cot²θ+1=cosec²θ


  • tanx.cotx=1
  • secx.cosx=1
  • sinx.cosecx=1

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